2y^2+10y=28

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Solution for 2y^2+10y=28 equation:


Simplifying
2y2 + 10y = 28

Reorder the terms:
10y + 2y2 = 28

Solving
10y + 2y2 = 28

Solving for variable 'y'.

Reorder the terms:
-28 + 10y + 2y2 = 28 + -28

Combine like terms: 28 + -28 = 0
-28 + 10y + 2y2 = 0

Factor out the Greatest Common Factor (GCF), '2'.
2(-14 + 5y + y2) = 0

Factor a trinomial.
2((-7 + -1y)(2 + -1y)) = 0

Ignore the factor 2.

Subproblem 1

Set the factor '(-7 + -1y)' equal to zero and attempt to solve: Simplifying -7 + -1y = 0 Solving -7 + -1y = 0 Move all terms containing y to the left, all other terms to the right. Add '7' to each side of the equation. -7 + 7 + -1y = 0 + 7 Combine like terms: -7 + 7 = 0 0 + -1y = 0 + 7 -1y = 0 + 7 Combine like terms: 0 + 7 = 7 -1y = 7 Divide each side by '-1'. y = -7 Simplifying y = -7

Subproblem 2

Set the factor '(2 + -1y)' equal to zero and attempt to solve: Simplifying 2 + -1y = 0 Solving 2 + -1y = 0 Move all terms containing y to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + -1y = 0 + -2 Combine like terms: 2 + -2 = 0 0 + -1y = 0 + -2 -1y = 0 + -2 Combine like terms: 0 + -2 = -2 -1y = -2 Divide each side by '-1'. y = 2 Simplifying y = 2

Solution

y = {-7, 2}

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